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Matthew Hunt on 8 Oct 2019
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Edited: Stephen23 on 21 Nov 2023
I have some data (x,f(x)) where 0<=x<=1 and I have N points. I wish to obtain f for an inteverval [a,b] which is well within the limits of 0 and 1, and on my end point, I get a NaN so some reason. I think my data set goes up from 0.001 to 0.999, and the set I want values for goes between 0.05 and 0.96. There is no extrapolation required.
What's going on exactly?
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dpb on 8 Oct 2019
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Show us the data and code...we can't guess.
Matthew Hunt on 8 Oct 2019
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I can't show you the data, it's proprietry.
The code is:
[SOC_c, index] = unique(SOC_c);
O_plus = interp1(SOC_c, OCV_c(index),SOC_cathode);
[SOC_a, index] = unique(SOC_a);
O_minus = interp1(SOC_a, OCV_a(index),SOC_anode);
dpb on 8 Oct 2019
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Then we really can't do much to help...your problem is data-specific
Matthew Hunt on 8 Oct 2019
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https://www.mathworks.com/matlabcentral/answers/484181-interp1-returns-nan-for-a-value#comment_753917
I really don't think it is. I think it's a problem with the interp1 routine personally.
If you are unwilling to help. I guess I will have to use something else or write my own routine.
dpb on 8 Oct 2019
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It's not that we're "unwilling" but if we can't reproduce an unspecified problem, what are we supposed to do? Buy the Crystal Ball Toolbox?
I be surprised if putting a set of x,y data into a .mat file and attaching it with no identifying info or context could possibly be of any real impact to your organization.
Or, if you wish, contact me directly thru my link thru the ML Contributors link and I'll destroy anything received once the issue is resolved one way or another.
Sciora Chang on 25 Oct 2021
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Have you solved this problem? I have met the exact same situation and couldn't figure out why.
dpb on 25 Oct 2021
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https://www.mathworks.com/matlabcentral/answers/484181-interp1-returns-nan-for-a-value#comment_1799428
As we told the original poster some two years ago, unless you post the data and the code, there's nothing can do beyond the general suggestions given here then -- interp1 has been around long enough that if there were some actual flaw in it, it is highly unlikely it wouldn't have been found long before now.
Attach the data at a minimum...
Michael Demkowicz on 21 Nov 2023
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- interpdata.mat
I've run into the same problem: interp1 returns a NaN at the endpoint of the interpolation range. I'm attaching the data to demonstrate the problem. I see NaN when I load the data and run the following commands:
nirrhor=interp1(irr,irrhor,r);
nirrhor(length(r))
Stephen23 on 21 Nov 2023
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https://www.mathworks.com/matlabcentral/answers/484181-interp1-returns-nan-for-a-value#comment_2970017
Edited: Stephen23 on 21 Nov 2023
Open in MATLAB Online
- interpdata.mat
"I've run into the same problem: interp1 returns a NaN at the endpoint of the interpolation range. I'm attaching the data to demonstrate the problem. I see NaN when I load the data and run the following commands"
Lets take a look:
S = load('interpdata.mat')
S = struct with fields:
irr: [10001×1 double] irrhor: [10001×1 double] r: [0 5.1557e-04 0.0010 0.0015 0.0021 0.0026 0.0031 0.0036 0.0041 0.0046 0.0052 0.0057 0.0062 0.0067 0.0072 0.0077 0.0082 0.0088 0.0093 0.0098 0.0103 0.0108 0.0113 … ] (1×11923 double)
V = interp1(S.irr,S.irrhor,S.r)
V = 1×11923
-0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058 -0.0058
X = find(isnan(V))
X = 11923
fprintf('%.42f %.42f\n', S.r([1,X]), S.irr([1,end])) % requested; supplied
0.000000000000000000000000000000000000000000 6.1466000000000002856381797755602747201919560.000000000000000000000000000000000000000000 6.146599999999999397459760075435042381286621
The last value you requested clearly lies outside the domain of your data. It is unclear what the problem is, everything seems to be working exactly as documented and expected.
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Answers (2)
Star Strider on 8 Oct 2019
You could have NaN values in your data. If so, first use the fillmissing function (R2016b and later reseases), then interp1.
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Matthew Hunt on 8 Oct 2019
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I checked and there are no problems with the data. There are some non-unique points which I removed but that shouldn't matter.
Star Strider on 8 Oct 2019
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https://www.mathworks.com/matlabcentral/answers/484181-interp1-returns-nan-for-a-value#comment_753927
If you are not extrapolating (that should only produce NaN values for the extrapolated values if you do not include a method designation and the 'extrap' argument), and there are no NaN values anywhere in your data, and we can’t see your data to test it, this will likely remain unsolved.
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Chris B on 27 Aug 2022
Moved: Image Analyst on 27 Aug 2022
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I ran into an issue where my start and endpoints were NaN. Turns out I was defining my x and xquery values differently. For example, try this code:
x=[500:2:1100]*10^-1;
xq=[500*10^-1 :2*10^-1: 1100*10^-1];
x==xq
x ~= xq because you are comparing floats in this case. Change 10^-1 to 10^1 and you'll get x==xq. So if you're getting NaNs, try making your x and xquery both integers and then dividing to get floats afterward.
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